Current File : //lib64/python3.9/site-packages/borg/shellpattern.py
import os
import re
def translate(pat, match_end=r"\Z"):
"""Translate a shell-style pattern to a regular expression.
The pattern may include ``**<sep>`` (<sep> stands for the platform-specific path separator; "/" on POSIX systems) for
matching zero or more directory levels and "*" for matching zero or more arbitrary characters with the exception of
any path separator. Wrap meta-characters in brackets for a literal match (i.e. "[?]" to match the literal character
"?").
Using match_end=regex one can give a regular expression that is used to match after the regex that is generated from
the pattern. The default is to match the end of the string.
This function is derived from the "fnmatch" module distributed with the Python standard library.
Copyright (C) 2001-2016 Python Software Foundation. All rights reserved.
TODO: support {alt1,alt2} shell-style alternatives
"""
sep = os.path.sep
n = len(pat)
i = 0
res = ""
while i < n:
c = pat[i]
i += 1
if c == "*":
if i + 1 < n and pat[i] == "*" and pat[i + 1] == sep:
# **/ == wildcard for 0+ full (relative) directory names with trailing slashes; the forward slash stands
# for the platform-specific path separator
res += fr"(?:[^\{sep}]*\{sep})*"
i += 2
else:
# * == wildcard for name parts (does not cross path separator)
res += r"[^\%s]*" % sep
elif c == "?":
# ? == any single character excluding path separator
res += r"[^\%s]" % sep
elif c == "[":
j = i
if j < n and pat[j] == "!":
j += 1
if j < n and pat[j] == "]":
j += 1
while j < n and pat[j] != "]":
j += 1
if j >= n:
res += "\\["
else:
stuff = pat[i:j].replace("\\", "\\\\")
i = j + 1
if stuff[0] == "!":
stuff = "^" + stuff[1:]
elif stuff[0] == "^":
stuff = "\\" + stuff
res += "[%s]" % stuff
else:
res += re.escape(c)
return "(?ms)" + res + match_end
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